Tommy Fury Says He’ll Knock Out Jake Paul Inside 4 Rounds

“Jake Paul is the next guy on my hit list.”

That’s Tommy Fury making it clear throughout a current discussion with TMZ Sports … he wishes to box fellow unbeaten fighter and bitter competitor, 25-year-old Jake Paul.

Of course, we have actually been here prior to. The guys were two times arranged to eliminate … however the bouts fell apart. But, simply last weekend in Dubai, Tommy and Jake almost concerned blows after Fury boxed an exhibit match on a Floyd Mayweather battle card.

This time, Tommy informs us he’s positive the 2 will make it all the method to the ring.

“I definitely feel like this fight will happen this time. I’ve said if this fight doesn’t happen it’ll be through no fault of my own,” Tommy says.

And, Fury says he terribly desires the battle.

“I want this fight more than anything because it’s a chance for me to put everything that I’ve been hearing for the past two years to bed. And it needs to be put to bed because at the end of the day this man is not in my class, he’s not in my league, and he’s a YouTube fighter, that’s what this man is. I’m a proper fighter. I’m from a fighting family. I have aspirations of winning world titles,” Tommy informs us.

Fury’s 8-0 with 4 KOs. Paul is 6-0 with 5 KOs. Jake’s combated some huge names in mixed martial arts, so his challengers are more identifiable. He’s beaten future UFC Hall of Famers Tyron Woodley (two times) and Anderson Silva.

As for where the battle might happen, Tommy’s believing huge. BIG.

(*4*)

FYI, Wembley is a substantial arena in London with a capability around 90K for boxing matches.

If/when the battle occurs … Fury would recommend you not to show up late, due to the fact that he’s preparing for a brief night’s work.

“This fight does not go the distance. There’s no chance in hell cause I won’t let it go to the distance. I am not gonna get in the ring and look to outpoint Jake Paul. I’m gonna be in that ring looking to take his head off with every punch.”

Then came the forecast.